What should the flow meter read in an open channel with a width of 36" and a water depth of 30" at a flow rate of 2 feet per second?

What should the flow meter read in an open channel with a width of 36" and a water depth of 30" at a flow rate of 2 feet per second?

• A. 5.25 MGD
• B. 9.69 MGD
• C. 10.50 MGD
• D. 12.00 MGD

Answer: (B)

To find the flow rate in million gallons per day (MGD) for an open channel based on the given parameters, we can use the formula for flow rate: \[ Q = A \times V \] where \( Q \) is the flow rate in cubic feet per second (CFS), \( A \) is the cross-sectional area of flow, and \( V \) is the velocity of the water. In this case, the width of the channel is 36 inches, which converts to feet as follows: \[ \text{Width} = 36 \text{ inches} = 3 \text{ feet} \] The water depth is given as 30 inches: \[ \text{Depth} = 30 \text{ inches} = 2.5 \text{ feet} \] Now, we can calculate the cross-sectional area \( A \): \[ A = \text{Width} \times \text{Depth} = 3 \text{ feet} \times 2.5 \text{ feet} = 7.5 \text{ square feet} \] Next, using the flow velocity of 2 feet per second, we can now calculate the flow rate \( Q \): \[

To find the flow rate in million gallons per day (MGD) for an open channel based on the given parameters, we can use the formula for flow rate:

[ Q = A \times V ]

where ( Q ) is the flow rate in cubic feet per second (CFS), ( A ) is the cross-sectional area of flow, and ( V ) is the velocity of the water.

In this case, the width of the channel is 36 inches, which converts to feet as follows:

[ \text{Width} = 36 \text{ inches} = 3 \text{ feet} ]

The water depth is given as 30 inches:

[ \text{Depth} = 30 \text{ inches} = 2.5 \text{ feet} ]

Now, we can calculate the cross-sectional area ( A ):

[ A = \text{Width} \times \text{Depth} = 3 \text{ feet} \times 2.5 \text{ feet} = 7.5 \text{ square feet} ]

Next, using the flow velocity of 2 feet per second, we can now calculate the flow rate ( Q ):

[